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If the base of an isosceles triangle is 11 and the perimeter is 39 what is the length of a leg?
If the base of an isosceles triangle is 11 and its perimeter is 39, then it has a height of 12.87.
What is the peremeter of the right angled triangle?
The perimeter is equal to the sum of (leg-1) plus (leg-2) plus (hypotenuse).
A right triangle has one leg two times as long as the other Find a function that models its perimeter P in terms of the length x of the shorter leg?
P = x3 + sqroot(x*x + x2*x2) x3 is the combined length of the two sides. Using pythagorean theory we find the hypotenuse, and add it to the other two sides to find the perimeter.
How does doubling the side legs of a right triangle affect its perimeter?
Doubling the lengths of the two legs of a right triangle increases each leg's contribution to the perimeter. If the original leg lengths are ( a ) and ( b ), the new lengths become ( 2a ) and ( 2b ). The original perimeter is ( a + b + c ) (where ( c ) is the hypotenuse), while the new perimeter becomes ( 2a + 2b + c' ) (where ( c' ) is the new hypotenuse). Thus, the new perimeter is effectively doubled, minus any increase in the hypotenuse, leading to a perimeter that is greater than or equal to twice the original perimeter.
What is the perimeter of the triangle if the short leg is 6 the hypotenuse is 12 and the long leg is 6radical 3?
that's easy...you just have to add 6 and 12. then you multiply the 6 times the radical 3 which is approximately 1.7. so 6+12=18 then 1.7x6=10.2. then you add 18 and 10.2 and you get 28.2. so the perimeter of the triangle is about 28.2 you would write it out like this: sides: 6+12+√3 perimeter: 18+√3= 28.2
A right triangle has one leg three times as long as the other Find a function that models its perimeter P in terms of the length x of the shorter leg?
The perimeter is the sum of all of the sides of the triangle. If the shorter leg is x, the longer leg is 3x. The hypotenuse is then the square root of x^2 + 3x^2, or 2x. Then the perimeter is x + 3x + 2x, simplified, f(x) = 6x.
If the base of an isosceles triangle is 11 and the perimeter is 39 what is the length of a leg?
If the base of an isosceles triangle is 11 and its perimeter is 39, then it has a height of 12.87.
The shorter leg of a 30 -60 -90 triangle is 9.4 feet long Find the perimeter?
Length of longer leg = 9.4 tan 60 = 16.28 feet Length of hypotenuse = 9.4 ÷ cos 60 = 18.8 feet Perimeter of triangle = 9.4 + 16.28 + 18.8 = 44.48 feet
What is the perimeter of a right triangle with an area of 6 and one leg measuring 3?
12
What is the peremeter of the right angled triangle?
The perimeter is equal to the sum of (leg-1) plus (leg-2) plus (hypotenuse).
A right triangle has one leg four times as long as the other Find a function that models its perimeter P in terms of the length x of the shorter leg?
Legs are 'x' and '4x'.Hypotenuse is sqrt(17x2) = x sqrt(17)Perimeter = x [ 5 + sqrt(17) ]
A right triangle has one leg two times as long as the other Find a function that models its perimeter P in terms of the length x of the shorter leg?
P = x3 + sqroot(x*x + x2*x2) x3 is the combined length of the two sides. Using pythagorean theory we find the hypotenuse, and add it to the other two sides to find the perimeter.
What is the perimeter of a right triangle if the hypotenuse is 51 inches and one leg is 24 inches?
Using Pythagoras' theorem the other leg is 45 inches So: 51+24+45 = 120 Perimeter = 120 inches
How does doubling the side legs of a right triangle affect its perimeter?
Doubling the lengths of the two legs of a right triangle increases each leg's contribution to the perimeter. If the original leg lengths are ( a ) and ( b ), the new lengths become ( 2a ) and ( 2b ). The original perimeter is ( a + b + c ) (where ( c ) is the hypotenuse), while the new perimeter becomes ( 2a + 2b + c' ) (where ( c' ) is the new hypotenuse). Thus, the new perimeter is effectively doubled, minus any increase in the hypotenuse, leading to a perimeter that is greater than or equal to twice the original perimeter.
What is the measure of a triangle with a hypotenuse of 37 and an adjacent leg of 12 and an opposite leg of 35?
It depends on what measure you want: the perimeter, the area, the size of the angles or something else. The question is not specific enough.
What is the perimeter of the triangle if the short leg is 6 the hypotenuse is 12 and the long leg is 6radical 3?
that's easy...you just have to add 6 and 12. then you multiply the 6 times the radical 3 which is approximately 1.7. so 6+12=18 then 1.7x6=10.2. then you add 18 and 10.2 and you get 28.2. so the perimeter of the triangle is about 28.2 you would write it out like this: sides: 6+12+√3 perimeter: 18+√3= 28.2
How do you find x in a right triangle?
That depends on what x is: a leg, an angle, what?
