You will have to measure it.
Period = 1 / frequency
Period = 1/frequency = 1/500 = 0.002 second = 2 milliseconds
Assuming that seconds refers to the period, the frequency is the reciprocal (1 / period in seconds). The height of the wave is irrelevant in this case.
Wave frequency f, and period of wave T are inverses, related by fT=1.
frequency = (wave speed)/(wavelength) frequency = 1/(period)
Period = 1 / frequency
Period = 1/frequency = 1/500 = 0.002 second = 2 milliseconds
Assuming that seconds refers to the period, the frequency is the reciprocal (1 / period in seconds). The height of the wave is irrelevant in this case.
If the period increases, the frequency decreases.The product of (frequency) times (period) is always ' 1 '.
Wave frequency f, and period of wave T are inverses, related by fT=1.
The frequency is the reciprocal of the period. If the period is doubled, the frequency will change by a factor of 1/2.
The frequency and period of a wave are inversely proportional. Therefore, as the frequency increases, the period decreases. frequency = 1/period period = 1/frequency
yes as, period time = 1/ frequency
Period = 1 / frequency
Period = 1 / frequency
frequency = (wave speed)/(wavelength) frequency = 1/(period)
Frequency = 1 / period