Suppose the number of Heads is H where H = 0, 1, 2, 3 ,4.
Then the number of Tails is 4-H.
Their product is X = H*(4-H) = 0, 3, 4, 3, 0
Thus X is NOT more than 1 only if H = 0 or H = 4
The probability of each of these events is 2-4 and so their combined probability is 2-3 = 1/8.
Therefore, Prob(X > 1 ) = 1 / 1/8 = 7/8
Coins do not have numbers, there is only the probability of heads or tails.
It is 0.5
It is 3/4
The odds are 50/50. A tossed coin does not have a memory.
It is 1/4.
Coins do not have numbers, there is only the probability of heads or tails.
50%
It is 0.5
The probability of tossing two heads in two coins is 0.25.
The probability is 0.5
It is 3/4
The number of times a coin is tossed does not alter the probability of getting heads, which is 50% in every case, as long as the coin has not been rigged (i.e., a double-headed coin, a weighted coin) to alter the result.
The odds are 50/50. A tossed coin does not have a memory.
The mathematical probability of getting heads is 0.5. 70 heads out of 100 tosses represents a probability of 0.7 which is 40% larger.
10 :)
thas so true
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