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Suppose the number of Heads is H where H = 0, 1, 2, 3 ,4.

Then the number of Tails is 4-H.

Their product is X = H*(4-H) = 0, 3, 4, 3, 0

Thus X is NOT more than 1 only if H = 0 or H = 4

The probability of each of these events is 2-4 and so their combined probability is 2-3 = 1/8.

Therefore, Prob(X > 1 ) = 1 / 1/8 = 7/8

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Q: How do you find the probability of x is more than 1 if a fair coin is tossed 4 times and x is the PRODUCT of the number of heads times the number of tails?
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