20 g = 20 * 9.807 = 196.14 (m/s)/s
radius = 29 ft (uk) = 8.839 metres
circumference = 2 * pi * 8.839 = 55.54 metres
if:
a = v^2 / r
then:
v = sq. root (a * r)
v = 41.64 metres / sec
41.64/55.54 = 0.75 rev / sec
0.75 * 60 = 45 rev / min
from power= torque*angular speed u can calculate torque and from torque u can find the force if the radius is known.
Its a mechanical rev limiter. Rotational centripetal force moves the balls of the govenor out in proportion to the rpm, this action is translated to a pressure release valve.
G-force (acceleration due to gravity) is a measure of the force applied to particles in a centrifuge, while RPM (revolutions per minute) is a measure of how fast the rotor of the centrifuge is spinning. The relationship between g and RPM depends on the rotor size and radius. RPM alone doesn't provide information on the actual force being applied to the particles, which is why g-force is often used as a more reliable measure in centrifugation.
The relationship between revolutions per minute (RPM) and relative centrifugal force (xg) is: g = (1.118 × 10-5) R S2 where g is the relative centrifugal force, R is the radius of the rotor in centimeters, and S is the speed of the centrifuge in revolutions per minute. You can use this for any centrifuge, just measure the radius of the rotor from the center to outer edge.
It depends on the generator that you use.
centripetal acceleration of a rotating object is equal to v^2/r so to sit on the edge of the spinning room and have a centripetal acceleration equal to 'g', (3.28 ft/s/s) your speed should be 12.687 ft/s or the RPM of the room should be 24.23 (circumference, 2 x pi x r, divided by speed gives times per rev., so 60 divided by this gives RPM)
Here are two formulae for centripetal acceleration:a = v2 / r (speed squared divided by the radius)a = omega2r (angular velocity squared, times the radius)The second formula seems simpler to use in this case. Just convert the angular speed to radians per second first. Remember that 1 minute = 60 seconds, and one revolution/second = 2 x pi radians/second.Oh, and you have to convert feet to meters, as well. 1 foot = 0.3048 meters.
Two formulas are commonly used for centripetal acceleration: 1) a = v2/r (v = speed, r = radius) 2) a = omega2 x r (omega = angular speed, r = radius) Formula 2 seems simpler to use in this case. Note that the angular speed must be in radians/second, so you must first convert rpm to radians per secnd.
That depends on the radius of the wheel making the revolutions.
You have to know how far the measurement point is from the center of the rotation.The farther out it is, the more meters per second it will cover.(At the same RPM, a 10-ft tractor tire covers more meters per second than a skate-board wheel does.)When you know the 'radius' of the wheel in meters,the speed of a point on the rim is(Radius) times (pi/30) times (RPM) = (Radius) times (0.1047) times (RPM) meters per second. (rounded)
It depends on the radius of the centrifuge. a=R x (angular frequency)^2 The units of angular frequency are radians/second, you want rpm If the rpm is 1 rpm the the angular frequency is 2pi *60 radians/sec
Furnaces have no RPM ratings