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How do you find the side length of a pentagon with an area of 50?
Wiki User
∙ 11y ago
Area of regular pentagon of side S = 5S2/4 tan 36
thus 5S2 = Area x 4 tan 36
(4 tan 36 = 2.906 near enough)
S2 = (50 x 2.906)/5
S = sqrt 29.06
= 5.39 inches
Wiki User
∙ 11y ago
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