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The diagonals bisect each other at right angles. So you could use Pythagoras on half the diagonals.

So, if the diagonals are a and b units long, then half the diagonals are a/2 and b/2 units long. Then, by Pythagoras, the sides of the rhombus are

sqrt[(a/2)2 + (b/2)2]

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Q: How do you find the sides of a rhombus if diagagonal are given?
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