for a linear function m= rise/ run
if given 2 points on the graph m= (y2-y1)/(x2-x1)
remember to simplify (lowest terms)!
the 2 behind the x and the y is are not exponents! They mean the range in the second bracket:
ex. (5,6)<--- 6= x2 5= x1
(7,8) <--- 8= y2 7=y1
Use point-slope formula
find the constant of variation and the slope of the given line from the graph of y=2.5x
we have to change the given equation to y=mx+b.here m is the slope
the slope is the 'm' in y=mx+b so even if the points aren't given, if there is an equation, then you can find the slope. for example, if you have an equation like this: y=2x+5 the slope is 2 and the y-intercept is 5.
I forgot. Go to coolmath.com to find the answer.
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Use: (y2 -y1)/(x2 -x1) to find the slope. Use: y -y1 = m(x -x1) to find the slope intercept equation whereas m is the slope.
To find the slope (steepness, not height) of a line when given two points, do the following: Slope = (y2-y1)/(x2-x1), where (x1, y1) is one point, and (x2,y2) is the second point.
y = {slope}x + {y intercept}
-1.5
To find the slope of a line passing through a given pair of points is found by using the point slope formula. Y(2)-Y(1) over x(2) -x(1).
Equation of given line: 3x + y = 15 or y = -3x + 15 Slope of given line = coefficient of x = -3 Slope of perperndicular = -1/(slope of given line) = -1 / (-3) = 1/3