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x*sqrt(2)/{5 - sqrt(3)} = {5 + sqrt(3)} => x*sqrt(2) = {5 + sqrt(3)} * {5 - sqrt(3)} = 25 - 3 = 22

=> x = 22/sqrt(2) = 22*sqrt(2)/{sqrt(2)*sqrt(2)} = 22*sqrt(2)/2 = 11*sqrt(2)

Q: How do you find the value of x if x root 2 divided by 5 minus root 3 equals 5 plus root 3?

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This is a simultaneous equation question: x-2y = -4 2x-y = 1 Multiply all terms in the top equation by 2: 2x-4y = -8 2x-y = 1 Subtract the bottom equation from the top equation remembering that a minus minus equals a plus: -3y = -9 Divide both sides of the equation by -3 to find the value of y remembering that a minus divided by a minus equals a plus: y = 3 Substitute the value of y into the original equations to find the value of x: Solution: x = 2 and y = 3

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