This is a simultaneous equation question:
x-2y = -4
2x-y = 1
Multiply all terms in the top equation by 2:
2x-4y = -8
2x-y = 1
Subtract the bottom equation from the top equation remembering that a minus minus equals a plus:
-3y = -9
Divide both sides of the equation by -3 to find the value of y remembering that a minus divided by a minus equals a plus:
y = 3
Substitute the value of y into the original equations to find the value of x:
Solution: x = 2 and y = 3
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i don't get that if it is 2xy +8 or 8 + 2xy then you can't solve or simplify it any further if it were 8 x 2y then you time the 8 by the 2 to get 16y
(2x)ysquared
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4xy + x3y + yx2 + yx + 3yx = x3y + x2y + 8xy = (xy)(x2y + x + 8)
3x3 - x2y + 12x - 4y = x2*(3x - y) + 4*(3x - y) = (x2 + 4)*(3x - y)