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It seems that it is the equation of an ellipse, x2/b2 + y2/a2 = 1, with center at the origin, a vertical major axis with length 2a, and a horizontal minor axis with length 2b.

x2/36 + y2/64 = 1

Since you are looking for the x-intercepts, they are (√b2, 0) = (√36, 0) = (6, 0) and (-√b2, 0) = (-√36, 0) = (-6, 0)

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10y ago
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Q: How do you find the x intercept for x2 36 plus y2 64 equals 1?
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