It seems that it is the equation of an ellipse, x2/b2 + y2/a2 = 1, with center at the origin, a vertical major axis with length 2a, and a horizontal minor axis with length 2b.
x2/36 + y2/64 = 1
Since you are looking for the x-intercepts, they are (√b2, 0) = (√36, 0) = (6, 0) and (-√b2, 0) = (-√36, 0) = (-6, 0)
36
I assume you mean. 4X - 3Y = -36 subtract 4X from each side -3Y = -4X -36 divide both sides by -3 Y = 4/3X + 12 12 is Y intercept
The x intercept is where y = 0. Substituting the value y = 0 into this equation gives: 36x2 = 1 x2 = 1/36 x = +- 1/6 So the intercepts are (1/6, 0) and (-1/6, 0)
9x+18y = 36 18y = -9x+36 y = -1/2x+2 which is now in slope intercept form the slope being -1/2
132
At the x-intercept, y = 0 So the equation becomes 4x = -36 or x = -9 So the x-intercept is (-9, 0)
36
I assume you mean. 4X - 3Y = -36 subtract 4X from each side -3Y = -4X -36 divide both sides by -3 Y = 4/3X + 12 12 is Y intercept
-9
The x intercept is where y = 0. Substituting the value y = 0 into this equation gives: 36x2 = 1 x2 = 1/36 x = +- 1/6 So the intercepts are (1/6, 0) and (-1/6, 0)
9x+18y = 36 18y = -9x+36 y = -1/2x+2 which is now in slope intercept form the slope being -1/2
132
62
72
Slope-intercept form is y = mx + b5x + 9y = -36Subtract 5x from each side:9y = -5x - 36Divide everything by 9:y = -5/9x - 4
36 inches plus what?
6x - 3y = 36 x intercept: If y = 0, then 6x=36 so x=6 y intercept: If x = 0, then -3y=36 so y = -12