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It seems that it is the equation of an ellipse, x2/b2 + y2/a2 = 1, with center at the origin, a vertical major axis with length 2a, and a horizontal minor axis with length 2b.

x2/36 + y2/64 = 1

Since you are looking for the x-intercepts, they are (√b2, 0) = (√36, 0) = (6, 0) and (-√b2, 0) = (-√36, 0) = (-6, 0)

Q: How do you find the x intercept for x2 36 plus y2 64 equals 1?

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36

I assume you mean. 4X - 3Y = -36 subtract 4X from each side -3Y = -4X -36 divide both sides by -3 Y = 4/3X + 12 12 is Y intercept

The x intercept is where y = 0. Substituting the value y = 0 into this equation gives: 36x2 = 1 x2 = 1/36 x = +- 1/6 So the intercepts are (1/6, 0) and (-1/6, 0)

9x+18y = 36 18y = -9x+36 y = -1/2x+2 which is now in slope intercept form the slope being -1/2

132

Related questions

At the x-intercept, y = 0 So the equation becomes 4x = -36 or x = -9 So the x-intercept is (-9, 0)

36

I assume you mean. 4X - 3Y = -36 subtract 4X from each side -3Y = -4X -36 divide both sides by -3 Y = 4/3X + 12 12 is Y intercept

-9

The x intercept is where y = 0. Substituting the value y = 0 into this equation gives: 36x2 = 1 x2 = 1/36 x = +- 1/6 So the intercepts are (1/6, 0) and (-1/6, 0)

9x+18y = 36 18y = -9x+36 y = -1/2x+2 which is now in slope intercept form the slope being -1/2

132

62

72

36 inches plus what?

Slope-intercept form is y = mx + b5x + 9y = -36Subtract 5x from each side:9y = -5x - 36Divide everything by 9:y = -5/9x - 4

27 + 9 = 36