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you use the equation y=mx+b; you use your point values to put in for x and y; slope is entered in for m and then you solve for b

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if you want to find the equation of a slope and point:

you use y-y*=m(x-x*)

the y* and x* are the numbers from your point

for example if you have the slope(m) 8/1 and the point (1,2)=(x*,y*)

then you would do the following-

1.........y - y* = m(x - x*)

2.........y - 2 = 8(x - 1)

3.........y - 2 = 8x - (-8)

4.........y - 2 = 8x + 8.........because eight x minus negative one equals eight x plus one

5.........y = 8x + 10.......because you add 2 to both sides of the equation

...........y = 8x + 10 is the equation answer

...........if you want to find the y-intercept from that:

6.........y-intercept equals (0,10)

Q: How do you find the y-intercept when you have the slope and a point?

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There is no slope nor intercept because there is no equation, simply an expression.

To find the slope, you must have at least two points, not one. You cannot find the slope at one point, because coordinate points do not have slopes - lines have slopes.

The slope of a curved line at a point is the slope of the tangent to the curve at that point. If you know the equation of the curve and the curve is well behaved, you can find the derivative of the equation of the curve. The value of the derivative, at the point in question, is the slope of the curved line at that point.

According to the question, you HAVE the point!

y-4=3/2(x-7)

Related questions

It shows the relationship of y in terms of x. [y = (yIntercept) + ((slope)*(x))] [slope = (y2 - y1)/(x2 - x1)]

There is no slope nor intercept because there is no equation, simply an expression.

You find the slope of the tangent to the curve at the point of interest.

You find the tangent to the curve at the point of interest and then find the slope of the tangent.

Use point-slope formula

To find the slope, you must have at least two points, not one. You cannot find the slope at one point, because coordinate points do not have slopes - lines have slopes.

You use point-slope form to find the equation of a line if you only have a point and a slope or if you are just given two point. Usually you will convert point-slope form to slope-intercept form to make it easier to use.

You can write it either in standard form (ax + by = c) or in slope-intercept form (y = mx + b)

The slope of a curved line at a point is the slope of the tangent to the curve at that point. If you know the equation of the curve and the curve is well behaved, you can find the derivative of the equation of the curve. The value of the derivative, at the point in question, is the slope of the curved line at that point.

According to the question, you HAVE the point!

By differentiating the answer and plugging in the x value along the curve, you are finding the exact slope of the curve at that point. In effect, this would be the slope of the tangent line, as a tangent line only intersects another at one point. To find the equation of a tangent line to a curve, use the point slope form (y-y1)=m(x-x1), m being the slope. Use the differential to find the slope and use the point on the curve to plug in for (x1, y1).

y-4=3/2(x-7)