Without an equality sign the terms given can't be considered to be a straight line equation
6x -1y = 9 y-intercept = -9
6x = 10-y y = -6x+10 The slope is -6 and the y intercept is 10
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-6x + y = 9 (+6x) -> y = 6x + 9
standard form (slope-intercept) is y = mx + b where m = slope and b = y intercept 6x + y = 12 subtract 6x from both sides y = -6x + 12 m = -6; b = 12
y = 6x+8 is already in slope intercept form
It is 0.
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