Without an equality sign the terms given can't be considered to be a straight line equation
6x -1y = 9 y-intercept = -9
6x = 10-y y = -6x+10 The slope is -6 and the y intercept is 10
-3
-3
-3
-3
24
To find the slope and y-intercept of the equation (2y = 6x), first rewrite it in slope-intercept form (y = mx + b). Dividing both sides by 2 gives (y = 3x). Here, the slope (m) is 3, and the y-intercept (b) is 0.
-6x + y = 9 (+6x) -> y = 6x + 9
To find the intercepts of the equation (6x + 8y = 24), we can set (y = 0) to find the x-intercept: [ 6x = 24 \implies x = 4 ] Thus, the x-intercept is ((4, 0)). Setting (x = 0) to find the y-intercept gives: [ 8y = 24 \implies y = 3 ] So, the y-intercept is ((0, 3)). Therefore, the intercepts are ((4, 0)) and ((0, 3)).
standard form (slope-intercept) is y = mx + b where m = slope and b = y intercept 6x + y = 12 subtract 6x from both sides y = -6x + 12 m = -6; b = 12
y = 6x+8 is already in slope intercept form