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p(x) = x4 + 2x3 + x2 + 8x - 12

When you go to graph this function, you make 'y' = p(x) .

At the y-intercept, 'x' is zero.

There, y = -12 .

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12y ago
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Q: How do you find the y intercept of p of x equals x to the fourth plus 2x cubed plus x squared plus 8x minus 12?
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