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no a plynomial can not have more zeros than the highest (degree) number of the function at leas that is what i was taught. double check the math.
For an algebraic function in one variable, as many as the highest power of the variable.
Assuming it is a function of "x", those are two different names for the same thing.
37,000,000,000
In general, there is no simple method.
12837000 (using calculator) or 3x4279 then add three zeros
the zeros of a function is/are the values of the variables in the function that makes/make the function zero. for example: In f(x) = x2 -7x + 10, the zeros of the function are 2 and 5 because these will make the function zero.
The integral zeros of a function are integers for which the value of the function is zero, or where the graph of the function crosses the horizontal axis.
zeros makes a matrix of the specified dimension, filled with zeros.
Answer using a calculator is 6048000 Another method: 20160 x 3 = 60480 (add the two zeros of 300) giving 6048000
You cannot. The function f(x) = x2 + 1 has no real zeros. But it does have a minimum.
Find All Possible Roots/Zeros Using the Rational Roots Test f(x)=x^4-81 ... If a polynomial function has integer coefficients, then every rational zero will ...
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The zeros of a quadratic function, if they exist, are the values of the variable at which the graph crosses the horizontal axis.
to report an answer with the correct number of significant figures, you may need to write significant zeros after the calculator number.
The integral zeros of a function are integers for which the value of the function is zero, or where the graph of the function crosses the horizontal axis.