You can get 24 out of these problems.
24x1, 12x2, 6x4, 3x8
(2*6)+8+4 = 24
[6*(6-4+2)]
24=4*6 4=2*2 6=2*3 24=2*2*2*3
The mean for 3,6,3,2,and 4 is 4. 3 + 6 + 3 + 2 + 4 + 6 = 24 24 / 6 = 4
add 2+5+6+6+2+4 which equals 24.but you get the 2 and 4 from the 24 that's in the problem.
2+2=4 6+4=10 10+14= 24 2+2+2=6 24+6=30
22
26
8*6**0.5 - 2*24**0.5 24**0.5= 4**0.5 * 6**0.5 24**0.5= 2*6**0.5 8*6**0.5 - 2*2*6**0.5 8*6**0.5 - 4*6**0.5 4*6**0.5
[[(9*2)/6]!-2]! 1) 9*2 = 18 2) 18/6 = 3 3) 3! = 6 4) 6-2 = 4 5) 4! = 24
Pairs of integers which when multiplied equal -24 are: -3 8 -4 6 -6 4 -12 2 -24 1 3 -8 4 -6 6 -4 12 -2 24 -1
If it is x² + 2x - 24, thenx² + 2x - 24 = (x + 6)(x - 4), since 6(-4) = 24 and 6 + (-4) = 2If it is x² - 2x - 24, thenx² - 2x - 24 = (x - 6)(x + 4), since (-6)(4) = 24 and -6 + 4 = -2If it is x2 = 2x - 24, thenx² = 2x - 24x² - 2x + 24 = 0Using the Quadratic Formula:-b ± √b²-4ac2a=2 ± √(-2)²-4(24)2=2 ± √4-962=2 ± √-922You cannot take the square root of a negative number, therefore x² = 2x - 24 is unfactorable.