How about 4 times 7 is 28 and 8 divded by 2 is 4
((7-2) * 4) + 8 = (5 * 4) + 8 = 20 + 8 = 28
[1 + (2 x 3)] x 4 = 28 = [1 + 6] x 4 = 7 x 4
The only common factors of 28 and 100 are 2, 4.
28 only has six factors: 1, 2, 4, 7, 14, 28.
2^3+(4*5)=8+20=28
How about 4 times 7 is 28 and 8 divded by 2 is 4
(4 x 5) + (2 x 4) = 28
5x2=10 10-3=7 7x4=28
5 x 3! - (4 - 2) = 30 - 2 = 28 5 x 3! - (4 ÷ 2) = 30 - 2 = 28 (2 x 3 x 5) - √4 = 30 - 2 = 28
((7-2) * 4) + 8 = (5 * 4) + 8 = 20 + 8 = 28
[1 + (2 x 3)] x 4 = 28 = [1 + 6] x 4 = 7 x 4
The only common factors of 28 and 100 are 2, 4.
4 + 4 + 4 + 4 + 4 + 4 + 4 / 4 = 7(4 + 4 + 4 + 4 + 4 + 4 + 4 = 28)(28 / 4 = 7)
This is the way to do it.. Factorize 4,28 using prime numbers only (Prime factorization) till you get 1,1. The prime numbers used are 2,2 & 7 Therefore HCF(4,28)= 2*2*7 = 28.
It would only have one rung, since the only common prime factor of 12, 16 and 26 is 2. 2)12,16,26
28 has only six factors: 1 2 4 7 14 28.