4 dvided by 2 minus 1 times 3
17 = (4+2)*3 - 1
It can be: 2*3+4+1 = 11
4 + 3 + 2 - 1 = 8
2^(4+1)-3
By dividing 1234 by 28: 1234 รท 28 = around 44.
17 = (4+2)*3 - 1
It can be: 2*3+4+1 = 11
3*(2+4)-1 = 17
4*4*2+2*3
4(2+3)-1=19
(3 x 4) + (2 - 1)
4 + 3 + 2 - 1 = 8
(1+4) x (2 x 3)
How about: 2*(1+3+4) = 16
2^(4+1)-3
Twelve of them.
2+3=5... 5x4=20... 20+1=21 !