4 dvided by 2 minus 1 times 3
17 = (4+2)*3 - 1
It can be: 2*3+4+1 = 11
You can achieve the number 36 by using the numbers 1, 2, 3, and 4 as follows: (1 + 2) × (3 + 4) = 3 × 7 = 21. However, to reach 36 specifically, you can use this formula: (4 × 3 × 2) + 1 = 24 + 12 = 36. This correctly combines the numbers to reach the desired total.
4 + 3 + 2 - 1 = 8
2^(4+1)-3
17 = (4+2)*3 - 1
It can be: 2*3+4+1 = 11
You can achieve the number 36 by using the numbers 1, 2, 3, and 4 as follows: (1 + 2) × (3 + 4) = 3 × 7 = 21. However, to reach 36 specifically, you can use this formula: (4 × 3 × 2) + 1 = 24 + 12 = 36. This correctly combines the numbers to reach the desired total.
4*4*2+2*3
3*(2+4)-1 = 17
4(2+3)-1=19
4 + 3 + 2 - 1 = 8
(1+4) x (2 x 3)
2^(4+1)-3
How about: 2*(1+3+4) = 16
To get 1000 using the numbers 1, 2, 3, and 4 only once in an equation, you can use the following mathematical expression: (4 x 2 x 3 x 1) x (4 + 2 + 3 + 1) = 1000. This equation involves multiplication and addition operations using all four numbers exactly once to achieve the desired result of 1000.
2+3=5... 5x4=20... 20+1=21 !