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3n+2 + (3n+3 - 3n+1) = 3n+1+1 + (3n+1+2 - 3n+1) = 3*3n+1 + (9*3n+1 - 3n+1)= (3+9-1)*3n+1 = 11*3n+1.

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Q: How do you get 3 to the power of n plus 2 plus (3 to the power of n plus 3 minus 3 to the power of n plus 1)?
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