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54 = 6 x 3 4/2

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54 = 6 x 3 4-2

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Q: How do you get 54 by using 6 3 4 2?
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What is the HCF of 18 54 and 81?

hcf(18, 54, 81) = 9. Using prime factorization: 18 = 2 x 3^2 54 = 2 x 3^3 81 = 3^4 hcf = 3^2 = 9


What 3 prime numbers multiply to make 54?

There are 4 of them which are 2*3*3*3 = 54


4 factors that will equal to 54 and are factors of 54?

2 x 3 x 3 x 3


What are 4 number that when multiply give 54?

As a product of its prime factors: 2*3*3*3 = 54


What 4 numbers multiplied equals 54?

As a product of its prime factors: 2*3*3*3 = 54


What is the GCF of 54 75 and 81?

gcf(54, 75, 81) = 3 54 = 2 x 3^3 75 = 3 x 5^2 81 = 3^4 gcf = 3


What is the missing number in the sequence 10-25-54-103-?

178 is the answer By using the formula a{n} = n³ + n² + 5n + 3 For e.g. A{2} =2 ³ +2²+5*2+3=25 =8+4+10+3=25 And so on.    = 10, 25, 54, 103, 178


Rationalize the Denominator- 2 square root of 24 plus square root 54?

(2√24) / √54 = (2√4√6) / (√9√6) = (4√6)/(3√6) = 4/3


What is the least common multiple of 54 and 48?

The LCM of 48 and 54 is 432. Prime factors of 48 are: 2^4 and 3 Prime factors of 54 are: 2 and 3^3 Multiplying the highest prime factors: 2^4 times 3^3 = 432 which is the LCM


What is 3 quarters of 54?

3/4 * 54 = 3(27)/2 = 81/2 = 40.5.


What are the factors of 108 and 54?

The factors of 54 are 1, 2, 6, 9, 27, and 54 The factors of 108 are 1, 2, 3, 4, 6, 9, 12, 18, 27, 36, 54, and 108


The first and fourth terms of a geometric progression are 54 and 2 respectively Find the sum to infinity of the geometric progression?

t(1) = a = 54 t(4) = a*r^3 = 2 t(4)/t(1) = r^3 = 2/54 = 1/27 and so r = 1/3 Then sum to infinity = a/(1 - r) = 54/(1 - 1/3) = 54/(2/3) = 81.