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Rationalize 5 over square root of 6?
The idea is to get rid of the square root in the denominator. For this purpose, you must multiply numerator and denominator by the square root of 6 in this case.
How do you rationalize denominator surds?
An example may help. If you have the fraction 1 / (2 + root(3)), where root() is the square root function, you multiply top and bottom by (2 - root(3)). If you multiply everything out, you will have no square root in the denominator, instead, you will have a square root in the numerator. If the denominator is only a root, eg root(3), you multiply top and bottom by root(3).
What is the rationalizes denominator of 42 divided by the square root of 7?
6
You can only use conjugates to rationalize the denominator when the denominator contains one radical term?
No, you can also use conjugates with more than one radical term. For example, if the denominator is root(2) + root(3), you can use the conjugate root(2) - root(3) to rationalize the denominator.
What is 1 minus the square root of 3 over 1 plus the square root of 3?
It looks like your question is [1-sqrt(3)] / [1+sqrt(3)], and you want to rationalize the denominator. If this is the case, multiply both numerator and denominator by (1-sqrt(3)), and get for the denominator = -2, and the numerator = 4 - 2*sqrt(3), so the answer is sqrt(3) - 2
