You cannot. With two containers, each with a capacity that is an even number of litres, you cannot get an odd number of litres.
-- Fill the 3 from the hose.-- Pour the 3 into the 5. The 5 container now has unfilled capacity of 2.-- Fill the 3 again from the hose.-- Pour the 3 slowly into the 5. It'll take only 2 to fill the 5 container.-- There is now 1 remaining in the 3 container. QED
You have to have something else to build the 4 liters into. Call it The Tub.Fill the 5.Pour the 5 into the 3.That leaves 2 liters in the 5.Pour them into The Tub. You now have 2 liters in The Tub.Empty the 3.Fill the 5.Pour the 5 into the 3.That leaves 2 liters in the 5.Pour them into The Tub. You now have 4 liters in The Tub.QEDYou do not have a TUB, it is not in the problem.Fill the 5 liter containerPour it into the 3 liter container leaving 2 liters in the 5 liter containerEmpty the 3 liter containerPour the 2 liters from the 5 liter container into the 3 liter containerFill the 5 liter containerFill the remainder of the 3 liter container from the 5 liter containerSince the 3 liter container already had 2 liters in it, one liter from the 5 liter container will fill it leaving 4 liters in the 5 liter container.Solved
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Assuming an unlimited supply of water, fill the 4 l. pour that onto the 9l. refill the 4l and pour that in the 9l. it now has 8l (not full) fill the 4l again pourinr carefully into the 9l leaving 3l in the 4l container. empty the 9l. pour the 3l from the 4 in to the 9l container. Refill the 4l. Pour that into the 9l (4+3 =7). fill the 4l again and pourinto the 9l leaving 2l in the 4l container. Dump the 9l container, pour in the 2l from the 4l container. fill the 4l again. pour into the 9l (2+4 = 6) and you are finished.
you need to drop your container (#1) into another larger container (#2) floating in a container of water (#3). Mark the water level in container #3 remove container #1 from #2. Fill container #3 back to the marked level measuring the number of litres used. Divide the number of litres used by a 1000 and you have the weight in metric tonnes
2 liters and 1/2 liter = 2,500 milliliters, IF he filled both of them.
There is most likely a more efficient way to do this, but this is the best I can do for now.Notation: ( x , y ) where x is the amount of water in the 5-liter container and y is the amount of water in the 7-liter container1. Fill the five-liter container ( 5 , 0 )2. Pour the five-liter container into the seven-liter container ( 0 , 5 )3. Fill the five-liter container ( 5 , 5 )4. Fill the seven-liter container with the five-liter container, leaving 3 liters in the five-liter container ( 3 , 7 )5. Pour out the seven-liter container ( 3 , 0 )6. Pour the five-liter container into the seven-liter container ( 0 , 3 )7. Fill the five-liter container ( 5 , 3 )8. Fill the seven-liter container with the five-liter container, leaving 1 liter in the five-liter container ( 1 , 7 )9. Pour out the seven-liter container ( 1 , 0 )10. Pour the five-liter container into the seven-liter container ( 0 , 1 )11. Fill the five-liter container ( 5 , 1 )12. Pour the five-liter container into the seven-liter container ( 0 , 6 )
-- Fill the 3 from the hose.-- Pour the 3 into the 5. The 5 container now has unfilled capacity of 2.-- Fill the 3 again from the hose.-- Pour the 3 slowly into the 5. It'll take only 2 to fill the 5 container.-- There is now 1 remaining in the 3 container. QED
As illustrated in the 1995 movie Die Hard 3 (Bruce Willis, Samuel K. Jackson), you can measure out exactly 7 liters in the following manner:Fill the 5 liter container, then use that 5 liters to fill the 3 liter container.Dump out the 3 liter container.What was left in the 5 gallon container is 2 liters. Pour this into the 3 liter container.Fill the 5 liter container again.You now have 7 liters : 5 in the large container and 2 in the smaller one.
Here's how to proceed:Fill container B with 3 liters.Pour the 3 liters from container B into container A.Fill container B again with 3 liters.Carefully pour from container B into container A, until container A is full.Container A already had 3 liters, so it only takes 2 more liters to fill it to 5 liters, leaving 1 liter remaining in container B.
all of it - the air would expand to fit the entire container.
2200 2200
You have to have something else to build the 4 liters into. Call it The Tub.Fill the 5.Pour the 5 into the 3.That leaves 2 liters in the 5.Pour them into The Tub. You now have 2 liters in The Tub.Empty the 3.Fill the 5.Pour the 5 into the 3.That leaves 2 liters in the 5.Pour them into The Tub. You now have 4 liters in The Tub.QEDYou do not have a TUB, it is not in the problem.Fill the 5 liter containerPour it into the 3 liter container leaving 2 liters in the 5 liter containerEmpty the 3 liter containerPour the 2 liters from the 5 liter container into the 3 liter containerFill the 5 liter containerFill the remainder of the 3 liter container from the 5 liter containerSince the 3 liter container already had 2 liters in it, one liter from the 5 liter container will fill it leaving 4 liters in the 5 liter container.Solved
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Notes: There is most likely a more efficient way to do this, but this is the best I can do for now.Notation: ( x , y ) where x is the amount of water in the 5-liter container and y is the amount of water in the 7-liter container1. Fill the five-liter container ( 5 , 0 )2. Pour the five-liter container into the seven-liter container ( 0 , 5 )3. Fill the five-liter container ( 5 , 5 )4. Fill the seven-liter container with the five-liter container, leaving 3 liters in the five-liter container ( 3 , 7 )5. Pour out the seven-liter container ( 3 , 0 )6. Pour the five-liter container into the seven-liter container ( 0 , 3 )7. Fill the five-liter container ( 5 , 3 )8. Fill the seven-liter container with the five-liter container, leaving 1 liter in the five-liter container ( 1 , 7 )9. Pour out the seven-liter container ( 1 , 0 )10. Pour the five-liter container into the seven-liter container ( 0 , 1 )11. Fill the five-liter container ( 5 , 1 )12. Pour the five-liter container into the seven-liter container ( 0 , 6 )
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