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Q: How do you get 8 with the numbers 1 2 3 and 4?

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Related questions

4 + 1 - 2 = 3

No, the numbers 1,1+2, 1+2+3, 1+2+3+4, 1+2+3+4+5... are triangular numbers.

2*4-3-1

It is: 2*(3+4)+1 = 15

4 x (3 + 2) - 1.

1 x 1 = 1 2 x 2 = 4 4 - 1 = 3 Answer: the numbers are 1 and 2

If it is integers, you have -2, -1, 0, 1, 2 and 3. If rational numbers or irrational numbers or real numbers, there are an infinity of them between -3 and 4.

If the digits are repeatable, the answer is 4*4*4*4. If the numbers cannot be repeated, then it is 4*3*2*1.

The prime numbers from 1 to 4 are 2 and 3.

32 + 1 - 4 or 4! + (3 x 2) -1 or 1(4! + 3 + 2) equal 29.

(4 + 1) x 3 + 2.

the answer is 3

1*1=1 2*2=4 3*3=9

Proof: First, we conduct prime numbers. 1=2-1 2 3=4-1 4 5=2-3*(-1) 7=4-3*(-1) 11=4*2-3*(-1) 13=4*(-3)+2-1 Then 6=32=(4-1)2 8=4*2 9=(-3)2 10=2*5=2*2-3*(-1) 12=3*4 14=7*2 15=5*3 16=8*2 31 =42*2-1

4! + (1 + 3)/2 = 24 + 4/2 = 24 + 2 = 26

To add mixed numbers with like denominators, first add the whole numbers, then add the fractions. For example: 2 2/3 + 4 1/3 = ?? First add the whole numbers. 2 2/3 + 4 1/3 = 6? Then add the fractions. 2 2/3 + 4 1/3 = 6 3/3 Simplify. 3/3 is one. 2 2/3 + 4 1/3 = 6 + 1 = 7.

6

1/4, 2/4, 3/4

4! * 2 + 1 - 3 =24*2 + 1 - 3 = 48 + 1 - 3 = 46

1+2=3 3+4=7 7x3=21 (1+2)x(3+4)

2

It could be: 1*(3+4)2 = 49

(2 x 4) + (3 x 1)

(4 + 3) * (2 - 1)

2*(4*3 - 1)