> Add 5 and 6 together and - 1
The previous answer give 10, not 9. Here's another way:
Using bar notation to denote an infinitely repeating decimal, 0.6666666... can be represented as .6 with a line drawn over the 6. The best I can do here is to put a line through the 6: .6 = 0.6666666..... If you were writing this by hand, you would put the line over the 6, not through it.
Then (5+1)/.6 = 9
6*5*1-6
It can be: (5*6)-21 = 28
6! = 720 ====
216 different codes
How do you add 9, 5, 3, and 1 in such a way to get sum of 21 by using only 6 numbers?You would add 9+5+3+1+1+2 and your answer would be 21.
3! = 6.
9 x 5 = 45 - 6 = 39 - 9 = 30 - 1 = 29.I know this and I'm 8!
6*5*4*3=360
Numbers from 1-6 that are odd numbers are 1, 3, and 5.
The two numbers are 6 and -5. 6 x (-5) = -30, 6 + (-5) = 1.
55----------------------------------------------------------------------------------------------From Rafaelrz.You can make, 5! = 120, five digit numbers using 1,2,3,4 and 6.
(9+1)^(8+7-6-5-4+2+3) = 10^5 = 100,000