The answer depends on what mathematical operations are permitted.
One set of solutions is:
8 = 5!/(5+5+5)
9 = 5 + 5 - 5/5
12 = .5*5!/sqrt(5*5)
NO besause 5s multiples are only numbers that end with 0 and 5s so no.....!!!
i think there are 18 digit 5s.
55 + 5/5
Numbers, listed in 5s and 10s, between 40 and 60 but including both numbers are:4045505560Numbers, listed in 5s and 10s, between 40 and 60 but excluding both numbers are:455055
4x5=20 20x4=80
NO besause 5s multiples are only numbers that end with 0 and 5s so no.....!!!
i think there are 18 digit 5s.
12
If: 5s = 33 Then: s = 33/5 = 6.6
55 + 5/5
Numbers, listed in 5s and 10s, between 40 and 60 but including both numbers are:4045505560Numbers, listed in 5s and 10s, between 40 and 60 but excluding both numbers are:455055
For every pair of 5s, the other two digits can be filled in 2 × 1 = 2 different ways. There are 3 positions the pair of 5s can sit (first and second, second and third, or third and fourth digits) → there are 3 × 2 = 6 different possible numbers (which are: 5589, 5598, 8559, 9558, 8955, 9855)
3s has a principle quantum number of n=3 5s has a principle quantum number of n=5
To write four 5s and make them represent 56 you need to write 55 + 5/5. When worked out it becomes 55 + 1 (5/5=1) which equals 56.
4x5=20 20x4=80
The answer is 9C4 = 9*8*7*6/(4*3*2*1) = 126 ways.
Ummmmm this did not help at all! never using this again!