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Q: How do you get the sum of the digit of a two digit number is 6?

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101117

-4

0

100000 2847239582

6

105

6

0

100,000 + 999,999 = 1,099,999

ok its 5

3201

1+2+3=6 1x2x3=6 123

100,000 + 99,999 = 199,999

420

The question is a bit ambiguous: "the sum of the product ... " does not seem to make sense. The first 5 digit number is 10000 the first 5 digit multiple of 6 is 10002 Their product is 100020000. I am not sure what to sum, though.

Four different digits that sum to 6 are: 0, 1, 2 & 3. The largest odd number that can be made from these is: 3201.

-2

101117

gentleman

The Answer is 36 btw. 3 + 6 = 9 3 x 6 = 2(3x6) 2(18) = 36

246642

60

This sum can be any of 14 (from the number 95 or 59), 12 (from the number 84 or 48), 10 (from the number 73 or 37), 8 (from the number 62 or 26), 6 (from the number 51 or 15), or 4 (from the number 40).

It is 58.

The way to know if a number is divisible by 3 is if its digit sum adds up to a number that is divisible by 3 (3, 6 or 9). The way to know if a number is divisible by 2 is if that number is even. That is, a number is divisible by two if the units are 0, 2, 4, 6 or 8. A number is divisible by 6 if it meets both these rules. In this case, 402 has the digit sum 6, and the units value is 2. Therefore, we can say that 402 is divisible by 6.