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If you want the graph to cross the x-axis at x = -2, then (x+2) is going to be a factor of the equation of the line.

If you want the graph to cross the x-axis at x = 2 and x = 6, then the two factors will be (x-2) and (x-6) and the equation of the line will be y = (x-2)(x-6). This simplifies to y = x2-8x+12.

In general, if you want to plot a graph with a line that crosses the x-axis at points x=a, x=b, x=c, x=d, ... where a,b,c,d... are integers, the equation of the line will be: y = (x-a)(x-b)(x-c)(x-d)...

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Q: How do you go about creating a graph with specific x intercepts like say at x equals -2 4 and 6?
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