If you want the graph to cross the x-axis at x = -2, then (x+2) is going to be a factor of the equation of the line.
If you want the graph to cross the x-axis at x = 2 and x = 6, then the two factors will be (x-2) and (x-6) and the equation of the line will be y = (x-2)(x-6). This simplifies to y = x2-8x+12.
In general, if you want to plot a graph with a line that crosses the x-axis at points x=a, x=b, x=c, x=d, ... where a,b,c,d... are integers, the equation of the line will be: y = (x-a)(x-b)(x-c)(x-d)...
One. It is a double root.
X intercept: -5 Y intercept: +3
for the equation:5x + 10y = 20, the two intercepts are:x = 0 , y = 2 or (0,2)y = 0 , x = 4 or (4,0)The graph is a straight line passing through the two intercepts (0,2) and (4,0)
Using the quadratic equation formula: x = -1/4 and x = 2/3
Equations don't have y-intercepts, but their graphs may. The y-intercept of the graph of the equation in this question is 0.7 .
One. It is a double root.
X intercept: -5 Y intercept: +3
Just one. It's at the origin. (0, 0)
x intercept = 5 y intercept = 15
The graph of x=5 is a vertical line on a set of coordinate axes that intercepts the x-axis at 5. Its slope is undefined.
It intercepts the y axis at (0, 5) and it intercepts the x axis at (-2.3, 0) passing through the I, II and III quadrants
for the equation:5x + 10y = 20, the two intercepts are:x = 0 , y = 2 or (0,2)y = 0 , x = 4 or (4,0)The graph is a straight line passing through the two intercepts (0,2) and (4,0)
Using the quadratic equation formula: x = -1/4 and x = 2/3
The statement - The graph of a system of equations with the same slope and the same y intercepts will have no solution is True
Equations don't have y-intercepts, but their graphs may. The y-intercept of the graph of the equation in this question is 0.7 .
Yes. A quadratic function can have 0, 1, or 2 x-intercepts, and 0, 1, or 2 y-intercepts.
The result will be a plane that intercepts the x-, y-, and z-axes at +9, +6, and +3, respectively.