So essentially, you are graphing some boundary with respect to -x=y correct. That is easy. Then do some analysis. Suppose x is in interval [0,k] for some real number k, then what is the region of y in which y <= -x? at 0, it's everything negative right?, at k it's everything less than -k right?
So the full region "below" the linear function f(x) = -x is your graph.
Draw it yourself.
At negative six on the x-axis, draw a vertical line. That line will be a solid line because we have that x is greater than OR EQUAL TO negative six. Then shade the right half of the graph -- which is where x has a value that is to the right (greater than) negative six
to graph in equaltities in two variables, you graph the two numbers and/or variables. then you look at the sign to see if its greater than, less than, greater than or equal to, or less than or equal to and you graph the line as dashed or a solid
Not sure what the "equal" on the end is for but zero is greater than negative one. -1<0 0>-1 -1<0<1
You have to flip the inequality sign. If it is less than(<) it has to become greater than(>). If it is greater than(>), it has to become less than(<). If it is less than equal to(<=), it has to become greater than equal to(>=). If it is greater than equal to(>=)., it must become less than equal to(<=).
Less than.
At negative six on the x-axis, draw a vertical line. That line will be a solid line because we have that x is greater than OR EQUAL TO negative six. Then shade the right half of the graph -- which is where x has a value that is to the right (greater than) negative six
Negative a is greater than, equal to or less than 0 depending on whether a, itself, is less than, equal to or greater than 0.
to graph in equaltities in two variables, you graph the two numbers and/or variables. then you look at the sign to see if its greater than, less than, greater than or equal to, or less than or equal to and you graph the line as dashed or a solid
-4 is greater than -8.
-6 is greater than -7
greater than.
x ≥ - 10.2 On a number line graph all real numbers to the right of -10.2. Use a closed dot to indicate that -10.2 is a solution.
Not sure what the "equal" on the end is for but zero is greater than negative one. -1<0 0>-1 -1<0<1
When the positive integer is greater than the negative integer.
You have to flip the inequality sign. If it is less than(<) it has to become greater than(>). If it is greater than(>), it has to become less than(<). If it is less than equal to(<=), it has to become greater than equal to(>=). If it is greater than equal to(>=)., it must become less than equal to(<=).
Less than.
8