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the slope is 1, and goes through the origin. It's a straight, diagonal line.

Q: How do you graph the linear equation x equals y?

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No, y=8 is a fixed value. A linear equation would look something like y=x+8 - That would produce a straight line graph if the values of x & y were plotted against each other on a graph.

no, because xx=x squared, and x squared is not linear

y = -x + 2The graph is a straight line, with [slope = -1], and passing through the point [y=2] on the y-axis.

y=x+2

Yes, it is a linear equation with no slope. The graph is a straight line (parallel to the x-axis) that passes through the y-axis, at {0,-3}

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No, y=8 is a fixed value. A linear equation would look something like y=x+8 - That would produce a straight line graph if the values of x & y were plotted against each other on a graph.

no, because xx=x squared, and x squared is not linear

y = -x + 2The graph is a straight line, with [slope = -1], and passing through the point [y=2] on the y-axis.

-1

y=x+2

The given equation y=3+x is a linear line with the slope of 1 and y-intercept of 3.

Yes, it is a linear equation with no slope. The graph is a straight line (parallel to the x-axis) that passes through the y-axis, at {0,-3}

if the linear equation is x+y=1 means we are having the graph points (1,0) (2,-1)....using this graph we can draw the graph

If you mean y = 2^x, then no, it is not a linear equation. This is an exponential equation. The graph of this exponential equation would start out near zero on the left-hand side (there is a horizontal asymptote at y = 0) and would gradually increase as you move to the right: overall, it has a curved shaped. If you mean y = 2x, then yes, it is a linear equation.

If: x-y = -2 then the x intercept is -2 and the y intercept is 2 So the points are: (-2, 0) and (0, 2)

That's a linear equation. The graph of it is a straight line with a slope of -1/2 and a y-intercept at y=1 .

Yes.