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A linear equation describes a line like 2x+1=y. If you were to graph that equation, then it would give you a line. A quadratic equation is like x^2+2x+1=y. Graphing this equation would give you a U shaped graph called a parabola.
To get the slope, you would have to do Y2-Y1 _____ X2-X1 or Rise ------ Run If you had two pairs of coordinates from a graph, the coordinates would be (X1, Y1) and (X2, Y2) For example, if you had the coordinate pairs (1,2) and (3,4) Your X1 would be 1, and your Y1 would be 2. So when you follow the equation Y2-Y1 _____ X2-X1 you would get 4-2 ----- 3-1 When you simplify, you would get 2/2 or 1. So your slope would be 1. Also, if you have an equation in Slope-Intercept Form, y=mx+b, your slope would be m. For example, if you had the equation y=3x+2, your slope would be 3.
The slope of a line containing two points (x1, y1) and (x2, y2) is given by:Slope = m = (y2 - y1)/(x2 - x1).So, we have these two points as (x1, y1) = (2, 4) and (x2, y2) = (4, 5).Let's find the slope m:m = (5 - 4)/(4 - 2) = 1/2.Since m > 0, then the line rises from left to right. The equation of the line is:(y - y1) = m(x - x1) This is the point slope form of a linear equation, let's use the first point:(y - 4) = (1/2)(x - 2)y - 4 = (1/2)x - 1y = (1/2)x + 3 This is the slope-intercept form of a linear equation, y = mx + bThe general form of a linear equation is Ax + By + C = 0;y = (1/2)x + 3(1/2)x -y + 3 = 0
yes it can if the exponent is 1.
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All the x's and all the y's in the equation must have no exponent (except '1').If you see an x2, or a square root of 'x' or 'y', or a y-1/2, or a y2, etc. then the graph is not a straight line.
if the linear equation is x+y=1 means we are having the graph points (1,0) (2,-1)....using this graph we can draw the graph
A linear equation describes a line like 2x+1=y. If you were to graph that equation, then it would give you a line. A quadratic equation is like x^2+2x+1=y. Graphing this equation would give you a U shaped graph called a parabola.
x2 -y2 =16 This is an equation that describes your problem. We can write this equation as (1/16)x2 -(1/16)y2 =1 You may recognize this as the equation whose graph is a hyperbola. So there are an infinite number of solutions.
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A linear equation is similar to a linear graph in that key data from the equation is clearly visible on the graph. A linear equation of y = 4x + 5 shows us that the y-intercept (or "b") is +5. This is where our line crosses the y-axis, and provides us with the information that the point (0, 5) exists on our line, making it the easiest point to draw on our graph every time! The equation also shows us that there is a slope (or "m") of 4. This means we must do the long-form of slope, which is "rise over run" or "change in y, divided by change in x". A slope of 4 is written as 4/1, or "four over one", showing we 'rise' 4 units on our graph, and 'run' 1 unit...clearly showing a slope of 4.
A non-linear graph. It could be a polynomial (of a degree greater than 1), a power function, a logarithmic or trigonometric graph. In fact any mathematical function other than a linear equation.
It means that for every '1' value of 'x', 'y' is increased by 0.159.
the slope is 1, and goes through the origin. It's a straight, diagonal line.
Since y=14x is a perfect linear relation, the correlation would be 1.
An example of an equation with a degree greater than 1 is (y = x^2 - 4x + 4). This is a quadratic equation, and its graph is a parabola, which does not produce a straight line. Since its highest exponent is 2, it is classified as degree 2, and the graph will show a curved shape rather than a linear one.