If you're trying to plot the curve y = x2, you can do so by plugging a few small values in as x, finding their corresponding y values, and marking those points on a graph. Then draw a "curve of best fit" that intersects all of those points. This particular curve would be a parabola moving upwards, with a focal point of (0, 0).
No translation will invert a quadratic graph.
the graph is moved down 6 units
x2+(y-x2/3)2=1
Select two points on the graph and suppose their coordinates are (x1, y1) and (x2, y2) then the gradient = (y1 - y2) / (x1 - x2) provided that x1 and x2 are different. If not, the gradient is not defined.
For the general straight line eq'n ; y = mx + c 'm' is the slope 'c' is the y-intercept. For a pair of point on a graph ( x1,y1,) & ( x2,y2) Then m = {y1 - y2) / ( x1 -x2) Note the 'y' co-ords go on the top , and the 'x' co-ods go on the botton. Note also The position of first term '1' and the second '2' term. Otherwise you will have a wrongly calculated slope/gradient.
y=x2+4x+1
The graph is a parabola facing (opening) upwards with the vertex at the origin.
y = (square root 1- x2) + (cube root x2)
you need 2 points on the line y2-y1 slope=----- x2-x1
9
y=x2
1