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you would go down 4 on the y-axis and the slope is 1 so then you would make a perfect diagonal line facing like this /

Q: How do you graph y x - 4?

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First convert it to Y= y-x+4=0 y=x-4 The graph has a slope of 1 and the y-intercept is (0,-4)

You subtract X from both sides, in which u get y=x-4; u should be able to graph that

y=x-2 y=x+4

The line x = 4 is a verticle line because, in a standard x-y graph, where x increases to the right and y increases upwards, the graph x = 4 is all points y, where x is 4. That is a verticle line, with infinite slope.

y=x2-4x+4 y = (x-2)(x-2) x=2 the graph only crosses the x-axis at positive 2. this is the minimum of the graph and the only point that is crosses the x-axis.

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First convert it to Y= y-x+4=0 y=x-4 The graph has a slope of 1 and the y-intercept is (0,-4)

y equals x-4 plus 2 is the same as y = x-2. You just translate the graph of y=x, 2 units to the right, OR 2 down.

You subtract X from both sides, in which u get y=x-4; u should be able to graph that

Y = x + 4

It is y = x + 4

y=x-2 y=x+4

To translate the graph y = x to the graph of y = x - 6, shift the graph of y = x down 6 units.

A graph with x and y coordinates has 4 quadrants, so would be a 4 quadrant graph.

The line x = 4 is a verticle line because, in a standard x-y graph, where x increases to the right and y increases upwards, the graph x = 4 is all points y, where x is 4. That is a verticle line, with infinite slope.

the equation should be y =-4/2x+1 that is a way to make it easier to graph

y=x2-4x+4 y = (x-2)(x-2) x=2 the graph only crosses the x-axis at positive 2. this is the minimum of the graph and the only point that is crosses the x-axis.

If for example: y = 2x+4 Then: y-2x = 4 And when the value of x is 0 then the y intercept is 4 And when the value of y is 0 then the x intercept is -2