y = 0x = y + 2plug 0 in for yx = 0 + 2x = 2
there is no right answer
-1.83 . . . . . and . . . . . -1.82
solve for y so if x + y = 0 then y = -x
It is: y = -7 which is a straight line parallel to the x axis
y = 0x = y + 2plug 0 in for yx = 0 + 2x = 2
there is no right answer
-1.83 . . . . . and . . . . . -1.82
(0,4) and (-2, 0)
A straight line through the points (0, 1) and (-0.4, 0).
solve for y so if x + y = 0 then y = -x
It is: y = -7 which is a straight line parallel to the x axis
The x intercept is at (84, 0) and the y intercept is at (0, 112) and so with a line join the points together which then will form a graph for the given equation.
If B=0, then the graph does not depend on the value of y. This is a vertical line at x = C/A
y 2 1 x 0 1 2
There are none. For this equation, there is nonreal answer, as the graph of the quadratic does not pass below the x-axis
When (the graph of the equations) the two lines intersect. The equations will tell you what the slopes of the lines are, just look at them. If they are different, then the equations have a unique solution..