Arrange all bags in serial and take one coin from first bag ,two coins from second bag three from third bag and take from all ten bags and weigh.
from the total weight we can calculate which bag has the coins of weight 27 grms.
Yes, you have as many bags as you please, (a minimum of two). You can have as many pieces of gold in the bags as you like and you can determine the weight of the coins as well, but the fake coins will weigh differently (more or less, it's up to you). You have a penny scale, meaning you can place something on a scale put a penny in and then receive a slip with the weight amount on it. If you don't want to see the solution don't continue reading. Answer: For the answer i will use simple denominations of weight. There are three bags with five pieces of gold in each bag. Each real piece weighs one pound and each fake piece weighs 1 pound one ounce. So you have bags A, B, and C and one is full of gold that is slightly heavier (fake). You take one coin from the first bag, two coins from the second, and three from the third and you put all 6 coins on the scale and weigh them. Now if all coins were real this should amount to 6 pounds, however, that isn't the case and you can determine the the fake bag by the overage weight. So for instance if the reading comes back with 6 pounds 2 ounces then bag B is the one with the fakes. Since every fake piece is one extra ounce and you're two ounces over it must be the bag that you took 2 coins from which would be bag B.. If it was 6 pounds 3 ounces then it would be bag C and 6 lbs one oz would be bag A. Alternatively, since you decide the amount of coins in each bag you could specifically say that you want one coin in the first bag two coins in the second, three in the third etc. and just weigh the bags together. Then you just follow the same train of thought to determine the fake bag.
¼ kilo = 1¾ bags (2 x 1¾ = 3½), so 1 bag weighs 4/7 of a quarter kilo, ie 1/7 of a kilo.
If you are certain two bags contain real gold, and if the three bags are supposed to be identical, then do the following. Find a balance scale. Take two of the bags and place one on each pan. If the scales balance, then the third one is bogus. Execute the guy who gave you that bag. If the scale fails to balance, you'll have to make another comparison. Remove the lighter bag and replace it with the third bag. If the scales balance, then the one you removed is bogus. Commence executions. If the scale fails to balance, then the heavier bag is bogus. Execute the fraud.
40 bags of anything that weigh 50 lbs each is one ton. A ton is 2000 lbs, so divide 2000 by 50.
It should weigh around 20 pounds. This can vary a bit though because the bags have varying levels of moisture can change the weight bag by bag.
Mass is measured in grams, not weight.
To measure the weight of a paper shopping bags you need a weighing scale. A weighing scale will give you the exact weight of the shopping bags.
The actual bag that the pot comes in, weighs approx .1-.2 grams. i bought an eighth for forty but he only had it in dimes, i got home and put it on my scale in and out of the bag. with the bags it weighted out at 4.0grams with out bags 3.1g
800 grams is 0.8 kg because there are 1000g in 1kg. 5x0.8kg is 4kg.
No, it is not harmful to keep coins in Ziploc bags.
It was something like this: There are twelve bags, each bag containing a random number of gold coins. Eleven bags contain genuine gold coins, each genuine coin weighing one-ounce apiece. One bag contains counterfeit coins, each counterfit coin weighing 9/10-ounces apiece. Using a scale to make only one measurement, how can you determine which bag is counterfeit?You have as many bags as you please, (a minimum of two). You can have as many pieces of gold in the bags as you like and you can determine the weight of the coins as well, but the fake coins will weigh differently (more or less, it's up to you). You have a penny scale, meaning you can place something on a scale put a penny in and then receive a slip with the weight amount on it.Answer:For the answer i will use simple denominations of weight. There are three bags with five pieces of gold in each bag. Each real piece weighs one pound and each fake piece weighs 1 pound one ounce.So you have bags A, B, and C and one is full of gold that is slightly heavier (fake).You take one coin from the first bag, two coins from the second, and three from the third and you put all 6 coins on the scale and weigh them.Now if all coins were real this should amount to 6 pounds, however, that isn't the case and you can determine the the fake bag by the overage weight.So for instance if the reading comes back with 6 pounds 2 ounces then bag B is the one with the fakes. Since every fake piece is one extra ounce and you're two ounces over it must be the bag that you took 2 coins from which would be bag B.. If it was 6 pounds 3 ounces then it would be bag C and 6 lbs one oz would be bag A.Alternatively, since you decide the amount of coins in each bag you could specifically say that you want one coin in the first bag two coins in the second, three in the third etc. and just weigh the bags together. Then you just follow the same train of thought to determine the fake bag.
hand bags
Yes, you have as many bags as you please, (a minimum of two). You can have as many pieces of gold in the bags as you like and you can determine the weight of the coins as well, but the fake coins will weigh differently (more or less, it's up to you). You have a penny scale, meaning you can place something on a scale put a penny in and then receive a slip with the weight amount on it. If you don't want to see the solution don't continue reading. Answer: For the answer i will use simple denominations of weight. There are three bags with five pieces of gold in each bag. Each real piece weighs one pound and each fake piece weighs 1 pound one ounce. So you have bags A, B, and C and one is full of gold that is slightly heavier (fake). You take one coin from the first bag, two coins from the second, and three from the third and you put all 6 coins on the scale and weigh them. Now if all coins were real this should amount to 6 pounds, however, that isn't the case and you can determine the the fake bag by the overage weight. So for instance if the reading comes back with 6 pounds 2 ounces then bag B is the one with the fakes. Since every fake piece is one extra ounce and you're two ounces over it must be the bag that you took 2 coins from which would be bag B.. If it was 6 pounds 3 ounces then it would be bag C and 6 lbs one oz would be bag A. Alternatively, since you decide the amount of coins in each bag you could specifically say that you want one coin in the first bag two coins in the second, three in the third etc. and just weigh the bags together. Then you just follow the same train of thought to determine the fake bag.
they are 1 coins
2 kg = 2 x 1000 grams = 2000 grams number of bags = 2000/250 = 8 bags
Uhhh no, why would they be?
5 bags = 5*2.2 kg = 11 kg = 11000 grams.