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You can't.

Actually you can.

(5 cubed + 5 + 55) / 5 = 37

Q: How do you make 37 using five 5's?

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It can't be done using only five 5s, but using six 5s you can get it: 37 = 555/(5+5+5) it can be done using five 5's (5+5/5) ** 5) + 5 ** = power operation actually the above should be written as: ((5+5)/5)^5 + 5 5!/(5+5) + (5*5) will work also

well here is how i wud do it................ 5 x 5 - 1 = 24

37 ÷ 5 = 7 2/5 = 7.4 or it can also be considered as 37 ÷ 5 = 7 remainder 2.

Five thousand, five hundred respectively.

They are fifty = 50 and five = 5

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5!/(5+5) + (5*5)

It can't be done using only five 5s, but using six 5s you can get it: 37 = 555/(5+5+5) it can be done using five 5's (5+5/5) ** 5) + 5 ** = power operation actually the above should be written as: ((5+5)/5)^5 + 5 5!/(5+5) + (5*5) will work also

If: 5s = 33 Then: s = 33/5 = 6.6

5x7=35, then 3-1=2, so 35+2=37

well here is how i wud do it................ 5 x 5 - 1 = 24

5/5=1 Keep this for later. so 2 5s used. Then do 5*5=25, so 5 5s used as 25 has a five in it, now do 1 - 25=24.

(5 x 5) x (5 - 5/5) = 100

37 ÷ 5 = 7 2/5 = 7.4 or it can also be considered as 37 ÷ 5 = 7 remainder 2.

The five on the left is ten times the five on the right.

Five thousand, five hundred respectively.

(5 x 5) + (5 x 5) + 5 = 25 + 25 + 5 = 50 + 5 = 55

The five on the left is ten times the five on the right.