You can't.
Actually you can.
(5 cubed + 5 + 55) / 5 = 37
It can't be done using only five 5s, but using six 5s you can get it: 37 = 555/(5+5+5) it can be done using five 5's (5+5/5) ** 5) + 5 ** = power operation actually the above should be written as: ((5+5)/5)^5 + 5 5!/(5+5) + (5*5) will work also
well here is how i wud do it................ 5 x 5 - 1 = 24
37 ÷ 5 = 7 2/5 = 7.4 or it can also be considered as 37 ÷ 5 = 7 remainder 2.
Five thousand, five hundred respectively.
They are fifty = 50 and five = 5
5!/(5+5) + (5*5)
It can't be done using only five 5s, but using six 5s you can get it: 37 = 555/(5+5+5) it can be done using five 5's (5+5/5) ** 5) + 5 ** = power operation actually the above should be written as: ((5+5)/5)^5 + 5 5!/(5+5) + (5*5) will work also
If: 5s = 33 Then: s = 33/5 = 6.6
5x7=35, then 3-1=2, so 35+2=37
well here is how i wud do it................ 5 x 5 - 1 = 24
5/5=1 Keep this for later. so 2 5s used. Then do 5*5=25, so 5 5s used as 25 has a five in it, now do 1 - 25=24.
37 ÷ 5 = 7 2/5 = 7.4 or it can also be considered as 37 ÷ 5 = 7 remainder 2.
The five on the left is ten times the five on the right.
Five thousand, five hundred respectively.
The five on the left is ten times the five on the right.
(5 x 5) + (5 x 5) + 5 = 25 + 25 + 5 = 50 + 5 = 55
They are fifty = 50 and five = 5