If: 5s = 33 Then: s = 33/5 = 6.6
55 is a bigger number than 5; 55 is in fact 11 5s.
(5*11)-5+5-5+5 I am sure that the number 11 is not allowed in this question. How about this: 5! - 55 - (5+5) = 55 For clarity, 5 factorial or 5! = 1x2x3x4x5 = 120
Two if you're writing, eleven if you're dividing.
The five on the left is ten times the five on the right.
It can't be done using only five 5s, but using six 5s you can get it: 37 = 555/(5+5+5) it can be done using five 5's (5+5/5) ** 5) + 5 ** = power operation actually the above should be written as: ((5+5)/5)^5 + 5 5!/(5+5) + (5*5) will work also
If: 5s = 33 Then: s = 33/5 = 6.6
5!/(5+5) + (5*5)
55 is a bigger number than 5; 55 is in fact 11 5s.
(5*11)-5+5-5+5 I am sure that the number 11 is not allowed in this question. How about this: 5! - 55 - (5+5) = 55 For clarity, 5 factorial or 5! = 1x2x3x4x5 = 120
55 + 5/5
55 of them.
One possibility is 55 + 5*5 = 55 + 25 = 80
Two if you're writing, eleven if you're dividing.
To write four 5s and make them represent 56 you need to write 55 + 5/5. When worked out it becomes 55 + 1 (5/5=1) which equals 56.
The five on the left is ten times the five on the right.
Five thousand, five hundred respectively.