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What numbers can you make with 4 4s?
Using four 4s, you can create a variety of numbers through mathematical operations. For example, you can make 1 by calculating (4 + 4)/(4 + 4), 2 by (4/4) + (4/4), and 3 by (4 + 4 + 4)/4. You can also create larger numbers such as 44 by concatenating two 4s. The possibilities are extensive when incorporating operations like addition, subtraction, multiplication, division, factorials, and decimal points.
How do you make 11 using four 4s?
4/.4 + 4/4 [= 10+1 = 11]
How do you make 11 using 4s only?
It could be: 4+4+4-4/4 = 11
How do you make 35 with four 4s?
44/4 + 4! = 11 + (4x3x2x1) = 11 + 24 = 35
How can you arrange 4 4s to make 35?
44/4 + 4! = 11 + (4x3x2x1) = 11 + 24 = 35
How do you make 11 only using 4 4s?
if you want to make eleven using only four 4s, this is the answer 4/.4+4/4(=10 + 1= 11) TA DA !
How do you make the numbers 21-40 with only 4s?
4/4 equals 1, so you can make practically any whole number from 4s. Just keep adding 4/4 together!
How can you make 13 using only 4 4s?
4! - 44/4 = 24 - 11 = 13
How do you make the numbers 0 50 using only four 4s?
how do i make 17 using only 2 4 6 8
How can make a total of 1000 by using fifteen 4s?
One possible way: Make a 10 using five 4s as follows: 4 + 4 + (4 + 4)/4 = 10 Make another two 10s using five 4s in each. Multiply these three 10s.
The difference of two numbers is 14 three times the larger number is 45 less than four times the smaller what are the two numbers?
Call the unknown numbers s and l for smaller and larger respectively. From the problem statement, l - s = 14 and 4s - 3l = 45. Transpose the first equation to result in l = 14 + s and substitute this into the second equation to result in 4s - 3(14 + s) =45, or 4s - 42 - 3s = 45. or s = 45 + 42 = 87. l is then 101.
How many bonds can Ca4s2 atom make without hybridization?
A Ca atom in its 4s^2 electron configuration can make up to 2 bonds without hybridization. This is because it has two unpaired electrons in its 4s orbital available for bonding.
