4+4=7 (+1), and 4x4=11(+5)
4/.4 + 4/4 [= 10+1 = 11]
It could be: 4+4+4-4/4 = 11
44/4 + 4! = 11 + (4x3x2x1) = 11 + 24 = 35
44/4 + 4! = 11 + (4x3x2x1) = 11 + 24 = 35
if you want to make eleven using only four 4s, this is the answer 4/.4+4/4(=10 + 1= 11) TA DA !
4/4 equals 1, so you can make practically any whole number from 4s. Just keep adding 4/4 together!
4! - 44/4 = 24 - 11 = 13
how do i make 17 using only 2 4 6 8
One possible way: Make a 10 using five 4s as follows: 4 + 4 + (4 + 4)/4 = 10 Make another two 10s using five 4s in each. Multiply these three 10s.
Call the unknown numbers s and l for smaller and larger respectively. From the problem statement, l - s = 14 and 4s - 3l = 45. Transpose the first equation to result in l = 14 + s and substitute this into the second equation to result in 4s - 3(14 + s) =45, or 4s - 42 - 3s = 45. or s = 45 + 42 = 87. l is then 101.
A Ca atom in its 4s^2 electron configuration can make up to 2 bonds without hybridization. This is because it has two unpaired electrons in its 4s orbital available for bonding.
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