This can not be done. Every non-negative number on the number line is the square root of its square. You would have to mark every number from zero on.
Look at the labels.
Mark off your number line in tenths. That's 2.2 and 3.1
Using Pythagoras Theorem: 5=22+12 Taking positive square root we get 1. Mark a point 'A' representing 2 units on number line. 2. Now construct AB of unit length perpendicular to OA. Join OB 3. Now taking O as centre and OB as radius draw an arc, intersecting number line at point C. 4. Point C represents on number line
A mark on the number one unit to the left of the zero point.
type in the number u want to find the square root of, then press the button with y over a check mark and x next to the check mark, then press 2 and hit = and there u goes! :P
At the number 2, draw a vertical line (perpendicular to the number line) and mark a distance of 1 unit on this line. Call this point X The distance from 0 to X is sqrt(5). Put a compass with its point at 0 and the pencil at X, and then draw an arc to cut the number line. That will be sqrt(5) on the number line.
-13 3 is on the left side of the zero mark on the number line.
This all depends on how you draw the number line. If you make the mark from 2 to 3 with 10 tenth marks, then 2.6 is located on the 6th mark from the left [or 4th mark from the right].
I assume you mean the square Root of 3. You can't show it exactly as root 3 is an irrational number. BUT, you can show it approximately. Root 3 = 1.732... So put a mark between 1 and 2 on the number line at about 1.7.
Look at the labels.
Mark off your number line in tenths. That's 2.2 and 3.1
A little past the "6" mark, past the "6.5" mark, past the "6.6" mark, right before the "6.65" mark. If you even have that many marks. :P Otherwise, you can just plot it somewhere reasonable on a number line with "6," "6.5," and "7."
At the point 1, draw a perpendicular to the number line. Mark of a length of 1 unit on this line: call that point A.From the 0 on the number line, using a pair of compasses, measure the arc OA and use that length to mark the number line at sqrt(2).Rationale:You have a right angled triangle, with its right angle at the point 1. The base is 1 unit and the vertical height is 1 unit. So, by Pythagoras, the line from 0 to A is sqrt(2) units.At the point 1, draw a perpendicular to the number line. Mark of a length of 1 unit on this line: call that point A.From the 0 on the number line, using a pair of compasses, measure the arc OA and use that length to mark the number line at sqrt(2).Rationale:You have a right angled triangle, with its right angle at the point 1. The base is 1 unit and the vertical height is 1 unit. So, by Pythagoras, the line from 0 to A is sqrt(2) units.At the point 1, draw a perpendicular to the number line. Mark of a length of 1 unit on this line: call that point A.From the 0 on the number line, using a pair of compasses, measure the arc OA and use that length to mark the number line at sqrt(2).Rationale:You have a right angled triangle, with its right angle at the point 1. The base is 1 unit and the vertical height is 1 unit. So, by Pythagoras, the line from 0 to A is sqrt(2) units.At the point 1, draw a perpendicular to the number line. Mark of a length of 1 unit on this line: call that point A.From the 0 on the number line, using a pair of compasses, measure the arc OA and use that length to mark the number line at sqrt(2).Rationale:You have a right angled triangle, with its right angle at the point 1. The base is 1 unit and the vertical height is 1 unit. So, by Pythagoras, the line from 0 to A is sqrt(2) units.
Set your strings up at one corner. Use the corner as a start point. From that corner measure out 3 feet and make a mark on the line. Next, on the other line measure out 4 feet and make a mark. Hold the end of your tape measure at one of the marks. Now have some one move the far end of the other string in and out until you line up the mark at 5 feet from the other mark. When you have a diagonal line of 5 feet from mark to mark, your corner will be square. You can now just measure from the lines that are now square to set the other lines.
Mark .75% of way from 0 to 1.
Draw the line (horizontally with positive numbers towards the right and negative numbers towards the left)) and mark the two numbers. The number which is further to the right along the line is greater than the other; alternatively, this can be expressed as: The number which is further to the left along the line is less than the other. If both numbers are the same point (mark) on the line, then they are equal.
The Density Property states that, between two rational numbers on a number line there is another rational number. Mark some fractions on a number line. No matter how dense the number line is, there still is another number between the two numbers.