This can not be done. Every non-negative number on the number line is the square root of its square. You would have to mark every number from zero on.
To represent the square root of 11.5 on a number line, we first need to approximate the value. The square root of 11.5 is approximately 3.39. On the number line, locate the whole number 3 and then estimate the position of 3.39 between 3 and 4. Mark this point on the number line to represent the square root of 11.5.
A number on a number line represents a specific value and its position relative to other numbers. Each point on the number line corresponds to a unique number, which can be positive, negative, or zero. To mark and label a point, you would locate the desired number on the line and place a dot or a marker at that position, then write the number next to it for clarity. For example, if you wanted to mark the number 3, you would find the point that is three units to the right of zero and label it as "3."
Look at the labels.
Mark off your number line in tenths. That's 2.2 and 3.1
A mark on the number one unit to the left of the zero point.
At the number 2, draw a vertical line (perpendicular to the number line) and mark a distance of 1 unit on this line. Call this point X The distance from 0 to X is sqrt(5). Put a compass with its point at 0 and the pencil at X, and then draw an arc to cut the number line. That will be sqrt(5) on the number line.
To represent the square root of 11.5 on a number line, we first need to approximate the value. The square root of 11.5 is approximately 3.39. On the number line, locate the whole number 3 and then estimate the position of 3.39 between 3 and 4. Mark this point on the number line to represent the square root of 11.5.
Oh, what a happy little question! To represent the square root of 3 on the number line, you simply find where it falls between whole numbers. Since the square root of 3 is between 1 and 2, you can place it around 1.7 on the number line with a little tick mark and a smile. Remember, there are no mistakes, just happy little accidents in math!
-13 3 is on the left side of the zero mark on the number line.
Look at the labels.
The square root of 29 is an irrational number, close to (but not equal to) 5.385; on a number line, this is a point between 5 and 6 closer to 5 than 6. The number can also be represented as a continued fraction. You can find a link to an image of this representation below.
On a number line, 2.6 would fall between 2 and 3. The number line represents the continuum of real numbers, with each point corresponding to a unique value. So, 2.6 would be located closer to 3 than to 2 on the number line.
Mark off your number line in tenths. That's 2.2 and 3.1
A little past the "6" mark, past the "6.5" mark, past the "6.6" mark, right before the "6.65" mark. If you even have that many marks. :P Otherwise, you can just plot it somewhere reasonable on a number line with "6," "6.5," and "7."
The positive square root of 115 lies between the positive square roots of 114 and 116.The positive square root of 115 lies between the positive square roots of 114 and 116.The positive square root of 115 lies between the positive square roots of 114 and 116.The positive square root of 115 lies between the positive square roots of 114 and 116.
At the point 1, draw a perpendicular to the number line. Mark of a length of 1 unit on this line: call that point A.From the 0 on the number line, using a pair of compasses, measure the arc OA and use that length to mark the number line at sqrt(2).Rationale:You have a right angled triangle, with its right angle at the point 1. The base is 1 unit and the vertical height is 1 unit. So, by Pythagoras, the line from 0 to A is sqrt(2) units.At the point 1, draw a perpendicular to the number line. Mark of a length of 1 unit on this line: call that point A.From the 0 on the number line, using a pair of compasses, measure the arc OA and use that length to mark the number line at sqrt(2).Rationale:You have a right angled triangle, with its right angle at the point 1. The base is 1 unit and the vertical height is 1 unit. So, by Pythagoras, the line from 0 to A is sqrt(2) units.At the point 1, draw a perpendicular to the number line. Mark of a length of 1 unit on this line: call that point A.From the 0 on the number line, using a pair of compasses, measure the arc OA and use that length to mark the number line at sqrt(2).Rationale:You have a right angled triangle, with its right angle at the point 1. The base is 1 unit and the vertical height is 1 unit. So, by Pythagoras, the line from 0 to A is sqrt(2) units.At the point 1, draw a perpendicular to the number line. Mark of a length of 1 unit on this line: call that point A.From the 0 on the number line, using a pair of compasses, measure the arc OA and use that length to mark the number line at sqrt(2).Rationale:You have a right angled triangle, with its right angle at the point 1. The base is 1 unit and the vertical height is 1 unit. So, by Pythagoras, the line from 0 to A is sqrt(2) units.
Set your strings up at one corner. Use the corner as a start point. From that corner measure out 3 feet and make a mark on the line. Next, on the other line measure out 4 feet and make a mark. Hold the end of your tape measure at one of the marks. Now have some one move the far end of the other string in and out until you line up the mark at 5 feet from the other mark. When you have a diagonal line of 5 feet from mark to mark, your corner will be square. You can now just measure from the lines that are now square to set the other lines.