(64m-3n)*7n*3m = 1344m2n - 63mn2
original problem: (m-24+9)-(3m-7n-12) distribute the negative sign: (m-24+9)+(-3m+7n+12) collect like terms: -2m+7n-3 that is as far as you can simplify this problem without knowing the values of m and n
Multiply by 100
Product means to multiply so it would be 7n.
7n = 91n = 91÷7n = 13
You don't have to do anything. 3m = 300cm.
This question as written can be taken two ways: 9m + 6n - 3m + 7n = 6m + 13n, or (9m + 6n) - (3m + 7n) = 9m + 6n - 3m - 7n = 6m - n
original problem: (m-24+9)-(3m-7n-12) distribute the negative sign: (m-24+9)+(-3m+7n+12) collect like terms: -2m+7n-3 that is as far as you can simplify this problem without knowing the values of m and n
Multiply by 100
Product means to multiply so it would be 7n.
7n(n−1)
7n = 91n = 91÷7n = 13
2(3m plus 7) using the distributave property 6m+14. maybe
7n-6 = 1
0 = 7(n + 4)21Use distributive property to multiply 7 by n and 4.0 = (7n + 28)21Use Distributive property to multiply 21 by 7n and 28.0 = 147n + 588Subtract 147n from both sides of the equation.-147n = 588Divide the entire equation by -147n.n = -4
You don't have to do anything. 3m = 300cm.
Yes, and here's the proof: Let's start out with the basic inequality 4 < 7 < 9. Now, we'll take the square root of this inequality: 2 < √7 < 3. If you subtract all numbers by 2, you get: 0 < √7 - 2 < 1. If √7 is rational, then it can be expressed as a fraction of two integers, m/n. This next part is the only remotely tricky part of this proof, so pay attention. We're going to assume that m/n is in its most reduced form; i.e., that the value for n is the smallest it can be and still be able to represent √7. Therefore, √7n must be an integer, and n must be the smallest multiple of √7 to make this true. If you don't understand this part, read it again, because this is the heart of the proof. Now, we're going to multiply √7n by (√7 - 2). This gives 7n - 2√7n. Well, 7n is an integer, and, as we explained above, √7n is also an integer; therefore, 7n - 2√7n is an integer as well. We're going to rearrange this expression to (√7n - 2n)√7, and then set the term (√7n - 2n) equal to p, for simplicity. This gives us the expression √7p, which is equal to 7n - 2√7n, and is an integer. Remember, from above, that 0 < √7 - 2 < 1. If we multiply this inequality by n, we get 0 < √7n - 2n < n, or, from what we defined above, 0 < p < n. This means that p < n and thus √7p < √7n. We've already determined that both √7p and √7n are integers, but recall that we said n was the smallest multiple of √7 to yield an integer value. Thus, √7p < √7n is a contradiction; therefore √7 can't be rational, and so must be irrational. Q.E.D.
n7-12