7n(n−1)
Wiki User
∙ 7y agon(2n - 1)(2n + 7)
100m^2-49n^2 (10m+7n)(10m-7n) the middle term cancels out.
3x squared minus 25x minus 28
n squared minus n
x = ? 42 = x squared minus x
It is 2n^3 + 7n^2 - 13n + 3
2-n-7n = 2-8n
n(2n - 1)(2n + 7)
Assuming you meant 7n (not just 7 at the end of your question) - first... simplify the equation. Numbers raised to powers get priority - so your new sum is... 5n - 64n + 25n + n + 7n.... This simplifies to... -26n
100m^2-49n^2 (10m+7n)(10m-7n) the middle term cancels out.
n > 2
3n2 - 7n = 0 n(3n - 7) = 0 So either n = 0 or 3n-7 = 0 ie, either n = 0 or n = 7/3 = 21/3 = 2.33...
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-7n2 + 74n + 33 = -7n2 + 77n - 3n + 33 = -7n*(n - 11) - 3*(n - 11) = =(-7n - 3)*(n - 11) = -(7n +3)*(n - 11)
3x squared minus 25x minus 28
n squared minus n
2x squared minus 4