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Multiply the three-digit number by the one's digit, or last digit, of the two-digit number. That is your first part. Now multiply by the second-to-last digit, or ten's digit, and multiply the result by 10. That is your second part. Add the two parts and that is your answer.
The largest one digit number that has three factors is 9. Its factors are 1, 3, and 9.
9 has three factors: 1, 3, and 9
One way to do this is multiply 8x3=24 so 24 has both as factors. Now multiply it by 10 and you have 240. That is a 3 digit number and sill has 8 and3 as factors.
9*4*2 = 72
Multiply 6 by 2000, then - since the factors have one decimal digit - separate the last digit in the result with a decimal point.
9 isn't prime, but one three-digit multiple of 18 is 108.
"Taking a cube" is the same basic procedure, whether it's a one-digit number, a three digit number, a complex number, a square matrix, or anything else you can multiply. Taking the cube simply means, multiply the number by itself, in such a way that it appears three times as a factor. For example, if your three-digit number is 235, you calculate the cube as 235 x 235 x 235.
The one digit number that has the same number of factors as the number six is three. Six's factors are 1, 2, 3, and 6 while three's factors are 1 and 3. Therefore, both numbers have the same number of factors.
It is 103 which is a prime number because it has only two factors which are itself and one
by one by one
Its Impossible. I say this because anything that is three digits divided by a one digit number that equals 8 is not possible. For example the higher 1 digit number that you can multiply by eight is nine so I did 8x9 and got 72 which is not a three digit number. The lowest three digit number that 8 goes into is 104 which is 13x8 and 13 is not a one digit number. Therefore the problem is impossible. :)