first we calculate the molecular weight M.W=158.11 mass of Na2S2O3=M.W*concentration*volume(in litter) for a concentration of 0.001 mass of Na2S2O3=158.11*0.001*1=0.15811 g so we use this mass and continue the volume to be 1 L
stanaderised of Na2S2O3 .
You do not need especially 25 grams to prepare 1.0 Liter 0.1N Na2S2O3-solution.It depends what substance is used: Na2S2O3 orNa2S2O3•5H2O (more common, called hypo).Molar masses are different, 158.11 g/mol for Na2S2O3 or(158.1 g/mol + 5*18.02 = ) 248.2 g/mol for Na2S2O3•5H2O respectively.To get the 0.10 N solution you'll need 15.8 gram or 24.8 gram respectively, dissolve it togather with 1 gram of disodium carbonate, and add up to 1.0 Liter (freshly boiled) water, let stand overnight and filter on fine grade paper.
Mol.Wt =248.17Molarity =( Wt/ Mol.Wt ) /No:of litres of solution0.1 =( Wt / 248.17) / 0.5Wt =0.1 *0.5*248.17Wt = 12.4085g in 500ml of solution.
Na2S2O3 oxidation number
hypo solution used in iodometric titration is sodiumthiosulphate. Its N\10 normality of Na2S2O3.
1167
Na2S2O3
+2
Sodium thiosulfate
Na2S2O3(aq) + 2HCL(aq) => 2NaCl(aq) + S(s) + SO2(g) + H2O(l)
a number