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Q: How do you prepare 300 mM dpph radical solution?
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How would you prepare a 300 ml of a 0.1 M Na CL solution from a solid Na CL solution and water?

You prepare a solution by dissolving a known mass of solute into a specific amount of solvent. In solutions, M is the molarity, or moles of solute per liter of solution. For 300 ml of a 0.1 M Na CL solution from a solid Na CL solution and water you need water and sodium chloride.


How many moles of potassium hydroxide are required to prepare 300 mL of 0.250 M solution?

Molarity = moles of solute/liters of solution ( 300 ml = 0.300 liter ) 0.250 molar KOH = moles KOH/0.300 liters = 0.075 moles KOH


How many moles of NaOH needed to prepare 300 mL of a 0.2 m solution of NaOH?

You need 2,4 g NaOH (0,06 moles).


What volume of 24 percent citric acid is needed to prepare eight 3 ounce bottles of 10 percent citric acid solution?

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What is the reduced radical form of 300?

300 = 100*3 So sqrt(300) = 10*sqrt(3)


What is the square root of 300 in radical form?

10 sqrt(3)


What quantity of a 80 percent acid solution must be mixed with a 30 percent solution to produce 300 mL of a 40 percent solution?

Let Q be the quantity of 80% solution required then (300 - Q) is the quantity of 30% solution as together the two solutions must equal 300. Then, [80 x Q] + [30 x (300 - Q)] = [40 x 300] 80Q + 9000 - 30Q = 12000 50Q = 3000 Q = 60...........which means (300 - Q) = 240 60ml of 80% acid solution + 240ml of 30% solution produces 300ml of 40% solution.


What is simplify radical terms 300?

I think you want: √300 = √(100 x 3) = √100 x √3 = 10√3


SC-300 Practice Test?

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What is the ditloid solution to - 300 L of NA in C?

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What is the exact value answers in degrees of two cos x minus radical three equals zero?

30 degrees explanation 2Cosx-radical 3=0 Then 2cosx=radical 3 and cos x=(radical 3)/2 Now remember that cos 300 is (radical 3)/2 from the 30/60/90 triangle. So the answer is 30 degrees.


Can 16 go into 300 evenly?

No, 18.75 is the solution.