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Let Q be the quantity of 80% solution required then (300 - Q) is the quantity of 30% solution as together the two solutions must equal 300. Then, [80 x Q] + [30 x (300 - Q)] = [40 x 300] 80Q + 9000 - 30Q = 12000 50Q = 3000 Q = 60...........which means (300 - Q) = 240 60ml of 80% acid solution + 240ml of 30% solution produces 300ml of 40% solution.
I think you want: √300 = √(100 x 3) = √100 x √3 = 10√3
No, 18.75 is the solution.
The statement "300 is between 100 and 400" is equivalent to: 100 < 300 < 400 Or the equivalent: 300 > 100 AND 300 < 400. If you check these statements and see that they are true, then 300 is between the two numbers.
You could do this by staring with the answer:150x2 = 300; 300+72 = 372; 372/6 = 62.(2x + 72)/6 = 62
You prepare a solution by dissolving a known mass of solute into a specific amount of solvent. In solutions, M is the molarity, or moles of solute per liter of solution. For 300 ml of a 0.1 M Na CL solution from a solid Na CL solution and water you need water and sodium chloride.
Molarity = moles of solute/liters of solution ( 300 ml = 0.300 liter ) 0.250 molar KOH = moles KOH/0.300 liters = 0.075 moles KOH
You need 2,4 g NaOH (0,06 moles).
300 ml
300 = 100*3 So sqrt(300) = 10*sqrt(3)
10 sqrt(3)
Let Q be the quantity of 80% solution required then (300 - Q) is the quantity of 30% solution as together the two solutions must equal 300. Then, [80 x Q] + [30 x (300 - Q)] = [40 x 300] 80Q + 9000 - 30Q = 12000 50Q = 3000 Q = 60...........which means (300 - Q) = 240 60ml of 80% acid solution + 240ml of 30% solution produces 300ml of 40% solution.
I think you want: √300 = √(100 x 3) = √100 x √3 = 10√3
SC-300 Practice Test is the best way to prepare and pass the SC-300 exam
300 Length of Noah's Ark in Cubits
30 degrees explanation 2Cosx-radical 3=0 Then 2cosx=radical 3 and cos x=(radical 3)/2 Now remember that cos 300 is (radical 3)/2 from the 30/60/90 triangle. So the answer is 30 degrees.
No, 18.75 is the solution.