Q: How do you prove a0 equals 1?

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No, because technically, it is not true.

It isn't equal, and any proof that they are equal is flawed.

Cannot prove that 2 divided by 10 equals 2 because it is not true.

(a to the power of 1)/(a to the power of 1)=1 So, a to the power of (1-1)=1 Therefore, a to the power of 0=1

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You can't it equals 2. You can't it equals 2.

Suppose the sequence is defined by an = a0 + n*d Then a1 = a0 + d = 15 and a13 = a0 + 13d = -57 Subtracting the first from the second: 12d = -72 so that d = -6 and then a0 - 6 = 15 gives a0 = 21 So a32 = 21 - 32*6 = -171

Using faulty logic.

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Using a calculator

yes

A= A0e^-kt A0= A/ e^kt = Ae^kt A0= A+ D* D*= A0- A D*= Ae^kt - A D*= A(e^kt - 1)

No, because technically, it is not true.

A0 is 1 meter square.

It isn't equal, and any proof that they are equal is flawed.

A0

If xyz=1, then it is very likely that x=1, y=1, and z=1. So plug these in. 1=logbase1of1, 1=logbase1of1, 1=logbase1of1. You end up with 1=1, 1=1, and 1=1. That's your proof.