Suppose the sequence is defined by an = a0 + n*d
Then a1 = a0 + d = 15
and a13 = a0 + 13d = -57
Subtracting the first from the second: 12d = -72 so that d = -6
and then a0 - 6 = 15 gives a0 = 21
So a32 = 21 - 32*6 = -171
The 90th term of the arithmetic sequence is 461
Find the 3nd term for 7.13.19
6
It is a + 8d where a is the first term and d is the common difference.
The difference between successive terms in an arithmetic sequence is a constant. Denote this by r. Suppose the first term is a. Then the nth term, of the sequence is given by t(n) = (a-r) + n*r or a + (n-1)*r
It is -173
The 90th term of the arithmetic sequence is 461
T(n) = 5n + 16
It is an arithmetic sequence if you can establish that the difference between any term in the sequence and the one before it has a constant value.
The nth term of an arithmetic sequence = a + [(n - 1) X d]
An arithmetic sequence
Find the 3nd term for 7.13.19
6
Arithmetic Sequence
Arithmetic- the number increases by 10 every term.
One number, such as 7101316 does not define a sequence.
The one number, 491419 does not constitute a sequence!