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What is the 32nd term of the arithmetic sequence where a1 equals 15 and a13 equals -57?

Anonymous

∙ 13y ago

Updated: 4/28/2022

Suppose the sequence is defined by an = a0 + n*d

Then a1 = a0 + d = 15

and a13 = a0 + 13d = -57

Subtracting the first from the second: 12d = -72 so that d = -6

and then a0 - 6 = 15 gives a0 = 21

So a32 = 21 - 32*6 = -171

Wiki User

∙ 13y ago

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