Because the diagonals of a rhombus intersect each other at 90 degrees whereas in a parallelogram they don't
a parallelogram with opposite equal acute angles, opposite equal obtuse angles, and four equal sides.
A parallelogram is a quadrilateral because it has 4 sides and all quadrilaterals have 4 sides such as a square, a rectangle, a rhombus ... etc
A quadrilateral, in general, is not a parallelogram. If it is a parallelogram then you will have some additional information about its sides and angles. If you do not have such information it is not possible to prove that it is a parallelogram. Draw a diagonal which will divide the quadrilateral into two triangles and use the additional information that you have to show that the triangles are congruent. This can then be used to show equality of sides or of angles: the latter can then be used to show that sides are parallel. Note that the choice of which diagonal may influence how (if at all) you proceed.
Try a vector approach.
You can use the distance formula to show that all four sides are the same length. The shape must, therefore, be a rhombus or square. If you then show that the length of the diagonal is sqrt(2) times the length of the side then, by Pythagoras, the diagonal and sides from a right angled triangle. The shape must, therefore, be a square.
Suppose that the parallelogram is a rhombus (a parallelogram with equal sides). If we draw the diagonals, isosceles triangles are formed (where the median is also an angle bisector and perpendicular to the base). Since the diagonals of a parallelogram bisect each other, and the diagonals don't bisect the vertex angles where they are drawn, then the parallelogram is not a rhombus.
a parallelogram with opposite equal acute angles, opposite equal obtuse angles, and four equal sides.
maths mental abuse to human s
A parallelogram is a quadrilateral because it has 4 sides and all quadrilaterals have 4 sides such as a square, a rectangle, a rhombus ... etc
Two congruent triangles.. To prove it, use the SSS Postulate.
A quadrilateral, in general, is not a parallelogram. If it is a parallelogram then you will have some additional information about its sides and angles. If you do not have such information it is not possible to prove that it is a parallelogram. Draw a diagonal which will divide the quadrilateral into two triangles and use the additional information that you have to show that the triangles are congruent. This can then be used to show equality of sides or of angles: the latter can then be used to show that sides are parallel. Note that the choice of which diagonal may influence how (if at all) you proceed.
I can use it when lines are joined together
A rhombus has two sets of parrallell sides. If it has two set of parrellell sides, it is a rhombus.
The diagonals divide the quadrilateral into four sections. You can then use the bisection to prove that opposite triangles are congruent (SAS). That can then enable you to show that the alternate angles at the ends of the diagonal are equal and that shows one pair of sides is parallel. Repeat the process with the other pair of triangles to show that the second pair of sides is parallel. A quadrilateral with two pairs of parallel lines is a parallelogram.
Parallelograms: 1.)opposite side of a parallelogram are parallel and you can prove that by finding the slope for both lines. 2.) opposite sides of a parallelogram are congruent 3.) diagonals bisect each other 4.)opposite angles are congruent 5.) consecutive angles are supp.
If it is a parallelogram, then it has two sets of parallelogram sides. Parallelograms' opposite angles are congruent A parallelogram's bisectors are congruent. * * * * * A parallelogram's bisectors are NOT congruent.
Yes, it is one of the ways to prove a figure is a rhombus. If adjacent sides are congruent, then the figure is a rhombus.