If you're given the inequality and the equation, then the way to prove that they have the same solution is to solve each one and show that the solutions are the same number. Don't strain yourself, though. An inequality and an equation never have the same solution.
Because the diagonals of a rhombus intersect each other at 90 degrees whereas in a parallelogram they don't
A parallelogram is a quadrilateral because it has 4 sides and all quadrilaterals have 4 sides such as a square, a rectangle, a rhombus ... etc
A quadrilateral, in general, is not a parallelogram. If it is a parallelogram then you will have some additional information about its sides and angles. If you do not have such information it is not possible to prove that it is a parallelogram. Draw a diagonal which will divide the quadrilateral into two triangles and use the additional information that you have to show that the triangles are congruent. This can then be used to show equality of sides or of angles: the latter can then be used to show that sides are parallel. Note that the choice of which diagonal may influence how (if at all) you proceed.
a parallelogram with opposite equal acute angles, opposite equal obtuse angles, and four equal sides.
If it is a parallelogram, then it has two sets of parallelogram sides. Parallelograms' opposite angles are congruent A parallelogram's bisectors are congruent. * * * * * A parallelogram's bisectors are NOT congruent.
Which of the following is a valid reason why the quadrilateral shown below is a parallelogram?
There are 5 ways to prove a Quadrilateral is a Parallelogram. -Prove both pairs of opposite sides congruent -Prove both pairs of opposite sides parallel -Prove one pair of opposite sides both congruent and parallel -Prove both pairs of opposite angles are congruent -Prove that the diagonals bisect each other
a rectangle has four right angles and opposite sides are all the same length This means that a parallelogram is not always a rectangle, but a rectangle is always a parallelogram, by definition.
If you're given the inequality and the equation, then the way to prove that they have the same solution is to solve each one and show that the solutions are the same number. Don't strain yourself, though. An inequality and an equation never have the same solution.
Because the diagonals of a rhombus intersect each other at 90 degrees whereas in a parallelogram they don't
A parallelogram is a quadrilateral because it has 4 sides and all quadrilaterals have 4 sides such as a square, a rectangle, a rhombus ... etc
I can use it when lines are joined together
If two opposite sides are congruent in length and direction then they are parallel sides. THat would mean the other two sides are congruent making 4 parallel sides or a parallelogram
A quadrilateral, in general, is not a parallelogram. If it is a parallelogram then you will have some additional information about its sides and angles. If you do not have such information it is not possible to prove that it is a parallelogram. Draw a diagonal which will divide the quadrilateral into two triangles and use the additional information that you have to show that the triangles are congruent. This can then be used to show equality of sides or of angles: the latter can then be used to show that sides are parallel. Note that the choice of which diagonal may influence how (if at all) you proceed.
Suppose that the parallelogram is a rhombus (a parallelogram with equal sides). If we draw the diagonals, isosceles triangles are formed (where the median is also an angle bisector and perpendicular to the base). Since the diagonals of a parallelogram bisect each other, and the diagonals don't bisect the vertex angles where they are drawn, then the parallelogram is not a rhombus.
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